(7x-1)(2x^2-x+3)=0

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Solution for (7x-1)(2x^2-x+3)=0 equation:


Simplifying
(7x + -1)(2x2 + -1x + 3) = 0

Reorder the terms:
(-1 + 7x)(2x2 + -1x + 3) = 0

Reorder the terms:
(-1 + 7x)(3 + -1x + 2x2) = 0

Multiply (-1 + 7x) * (3 + -1x + 2x2)
(-1(3 + -1x + 2x2) + 7x * (3 + -1x + 2x2)) = 0
((3 * -1 + -1x * -1 + 2x2 * -1) + 7x * (3 + -1x + 2x2)) = 0
((-3 + 1x + -2x2) + 7x * (3 + -1x + 2x2)) = 0
(-3 + 1x + -2x2 + (3 * 7x + -1x * 7x + 2x2 * 7x)) = 0
(-3 + 1x + -2x2 + (21x + -7x2 + 14x3)) = 0

Reorder the terms:
(-3 + 1x + 21x + -2x2 + -7x2 + 14x3) = 0

Combine like terms: 1x + 21x = 22x
(-3 + 22x + -2x2 + -7x2 + 14x3) = 0

Combine like terms: -2x2 + -7x2 = -9x2
(-3 + 22x + -9x2 + 14x3) = 0

Solving
-3 + 22x + -9x2 + 14x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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